The final teams had been decided just before the start of the 1896 cable match. The Americans were to be represented by H.N. Pillsbury, J.W. Showalter, C.F. Burille, J.F. Barry, E. Hymes, A.B. Hodges, E. Delmar, and D.G. Baird.
The eight players chosen to represent the British side were J.H. Blackburne, A. Burn, H.E. Bird, S. Tinsley, C.D. Locock, D.Y. Mills, H.E. Atkins, and E.M. Jackson.
The American team won the toss and had the White pieces on boards 1, 3, 5, and 7. By the time the 7:00pm adjournment arrived, none of the games had been decided. Showalter had the most dominating position at board # 2 against Burn. Blackburne looked to have a slight edge on Pillsbury at board # 1, after a poor start in the opening. Jackson had an impressive attacking position on Baird at board # 8. All other games appeared to be fairly even going into the second day.
Play was resumed at 10:00am (EST) the following day on Saturday, March 14th. Showalter won his game over Burn as expected. Bird surprisingly lost his game to Burille at board # 3, which proved to be costly to the British hopes. Barry outplayed Tinsley in the end game on board # 4. This gave the Americans three outright victories thus far, a commanding lead.
Jackson would go on to win his game over Baird, and Pillsbury would eventually succumb to Blackburne. The rest of the games ended in fiercely contested draws, giving the Americans the overall victory by the score of 4 1/2 – 3 1/2. The game that seemed to decide the match between C.F. Burille and H.E. Bird is shown below, as well as the final results:
| America | Great Britain | |||
| 1. | Pillsbury | 0 | Blackburne | 1 |
| 2. | Showalter | 1 | Burn | 0 |
| 3. | Burille | 1 | Bird | 0 |
| 4. | Barry | 1 | Tinsley | 0 |
| 5. | Hymes | 1/2 | Locock | 1/2 |
| 6. | Hodges | 1/2 | Mills | 1/2 |
| 7. | Delmar | 1/2 | Atkins | 1/2 |
| 8. | Baird | 0 | Jackson | 1 |
| 4 1/2 | 3 1/2 |


















